Optimal. Leaf size=219 \[ \frac{\left (-5 a^2 b c d^2+a^3 d^3+15 a b^2 c^2 d+5 b^3 c^3\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{5/2} \sqrt{d}}+\frac{\sqrt{a+b x} \sqrt{c+d x} (5 b c-a d) (a d+b c)}{8 b^2}-2 \sqrt{a} c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}+\frac{\sqrt{a+b x} (c+d x)^{3/2} (a d+5 b c)}{12 b} \]
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Rubi [A] time = 0.222086, antiderivative size = 219, normalized size of antiderivative = 1., number of steps used = 9, number of rules used = 8, integrand size = 22, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.364, Rules used = {101, 154, 157, 63, 217, 206, 93, 208} \[ \frac{\left (-5 a^2 b c d^2+a^3 d^3+15 a b^2 c^2 d+5 b^3 c^3\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{5/2} \sqrt{d}}+\frac{\sqrt{a+b x} \sqrt{c+d x} (5 b c-a d) (a d+b c)}{8 b^2}-2 \sqrt{a} c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}+\frac{\sqrt{a+b x} (c+d x)^{3/2} (a d+5 b c)}{12 b} \]
Antiderivative was successfully verified.
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Rule 101
Rule 154
Rule 157
Rule 63
Rule 217
Rule 206
Rule 93
Rule 208
Rubi steps
\begin{align*} \int \frac{\sqrt{a+b x} (c+d x)^{5/2}}{x} \, dx &=\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}-\frac{1}{3} \int \frac{(c+d x)^{3/2} \left (-3 a c+\frac{1}{2} (-5 b c-a d) x\right )}{x \sqrt{a+b x}} \, dx\\ &=\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}-\frac{\int \frac{\sqrt{c+d x} \left (-6 a b c^2-\frac{3}{4} (5 b c-a d) (b c+a d) x\right )}{x \sqrt{a+b x}} \, dx}{6 b}\\ &=\frac{(5 b c-a d) (b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{8 b^2}+\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}-\frac{\int \frac{-6 a b^2 c^3-\frac{3}{8} \left (5 b^3 c^3+15 a b^2 c^2 d-5 a^2 b c d^2+a^3 d^3\right ) x}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx}{6 b^2}\\ &=\frac{(5 b c-a d) (b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{8 b^2}+\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}+\left (a c^3\right ) \int \frac{1}{x \sqrt{a+b x} \sqrt{c+d x}} \, dx+\frac{\left (5 b^3 c^3+15 a b^2 c^2 d-5 a^2 b c d^2+a^3 d^3\right ) \int \frac{1}{\sqrt{a+b x} \sqrt{c+d x}} \, dx}{16 b^2}\\ &=\frac{(5 b c-a d) (b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{8 b^2}+\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}+\left (2 a c^3\right ) \operatorname{Subst}\left (\int \frac{1}{-a+c x^2} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )+\frac{\left (5 b^3 c^3+15 a b^2 c^2 d-5 a^2 b c d^2+a^3 d^3\right ) \operatorname{Subst}\left (\int \frac{1}{\sqrt{c-\frac{a d}{b}+\frac{d x^2}{b}}} \, dx,x,\sqrt{a+b x}\right )}{8 b^3}\\ &=\frac{(5 b c-a d) (b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{8 b^2}+\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}-2 \sqrt{a} c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )+\frac{\left (5 b^3 c^3+15 a b^2 c^2 d-5 a^2 b c d^2+a^3 d^3\right ) \operatorname{Subst}\left (\int \frac{1}{1-\frac{d x^2}{b}} \, dx,x,\frac{\sqrt{a+b x}}{\sqrt{c+d x}}\right )}{8 b^3}\\ &=\frac{(5 b c-a d) (b c+a d) \sqrt{a+b x} \sqrt{c+d x}}{8 b^2}+\frac{(5 b c+a d) \sqrt{a+b x} (c+d x)^{3/2}}{12 b}+\frac{1}{3} \sqrt{a+b x} (c+d x)^{5/2}-2 \sqrt{a} c^{5/2} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )+\frac{\left (5 b^3 c^3+15 a b^2 c^2 d-5 a^2 b c d^2+a^3 d^3\right ) \tanh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b} \sqrt{c+d x}}\right )}{8 b^{5/2} \sqrt{d}}\\ \end{align*}
Mathematica [A] time = 0.899742, size = 274, normalized size = 1.25 \[ \frac{\sqrt{c+d x} \left (-\frac{b \sqrt{d} \left (\sqrt{a+b x} (c+d x) \left (-3 a^2 d^2+2 a b d (7 c+d x)+b^2 \left (33 c^2+26 c d x+8 d^2 x^2\right )\right )-48 \sqrt{a} b^2 c^{5/2} \sqrt{c+d x} \tanh ^{-1}\left (\frac{\sqrt{c} \sqrt{a+b x}}{\sqrt{a} \sqrt{c+d x}}\right )\right )}{\sqrt{\frac{b (c+d x)}{b c-a d}}}-3 \sqrt{b c-a d} \left (-5 a^2 b c d^2+a^3 d^3+15 a b^2 c^2 d+5 b^3 c^3\right ) \sinh ^{-1}\left (\frac{\sqrt{d} \sqrt{a+b x}}{\sqrt{b c-a d}}\right )\right )}{24 b^2 \sqrt{d} (a d-b c) \sqrt{\frac{b (c+d x)}{b c-a d}}} \]
Antiderivative was successfully verified.
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Maple [B] time = 0.013, size = 583, normalized size = 2.7 \begin{align*}{\frac{1}{48\,{b}^{2}}\sqrt{bx+a}\sqrt{dx+c} \left ( 16\,{x}^{2}{b}^{2}{d}^{2}\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}+3\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{a}^{3}{d}^{3}-15\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{a}^{2}bc{d}^{2}+45\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}a{b}^{2}{c}^{2}d+15\,\ln \left ( 1/2\,{\frac{2\,bdx+2\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}+ad+bc}{\sqrt{bd}}} \right ) \sqrt{ac}{b}^{3}{c}^{3}-48\,\sqrt{bd}\ln \left ({\frac{adx+bcx+2\,\sqrt{ac}\sqrt{d{x}^{2}b+adx+bcx+ac}+2\,ac}{x}} \right ) a{b}^{2}{c}^{3}+4\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}xab{d}^{2}+52\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}x{b}^{2}cd-6\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}{a}^{2}{d}^{2}+28\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}abcd+66\,\sqrt{d{x}^{2}b+adx+bcx+ac}\sqrt{bd}\sqrt{ac}{b}^{2}{c}^{2} \right ){\frac{1}{\sqrt{d{x}^{2}b+adx+bcx+ac}}}{\frac{1}{\sqrt{bd}}}{\frac{1}{\sqrt{ac}}}} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F(-2)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Exception raised: ValueError} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [A] time = 49.3773, size = 2732, normalized size = 12.47 \begin{align*} \text{result too large to display} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\sqrt{a + b x} \left (c + d x\right )^{\frac{5}{2}}}{x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [A] time = 1.82513, size = 448, normalized size = 2.05 \begin{align*} -\frac{2 \, \sqrt{b d} a c^{3}{\left | b \right |} \arctan \left (-\frac{b^{2} c + a b d -{\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}}{2 \, \sqrt{-a b c d} b}\right )}{\sqrt{-a b c d} b} + \frac{1}{24} \, \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d} \sqrt{b x + a}{\left (2 \,{\left (b x + a\right )}{\left (\frac{4 \,{\left (b x + a\right )} d^{2}{\left | b \right |}}{b^{4}} + \frac{13 \, b^{9} c d^{5}{\left | b \right |} - 7 \, a b^{8} d^{6}{\left | b \right |}}{b^{12} d^{4}}\right )} + \frac{3 \,{\left (11 \, b^{10} c^{2} d^{4}{\left | b \right |} - 4 \, a b^{9} c d^{5}{\left | b \right |} + a^{2} b^{8} d^{6}{\left | b \right |}\right )}}{b^{12} d^{4}}\right )} - \frac{{\left (5 \, \sqrt{b d} b^{3} c^{3}{\left | b \right |} + 15 \, \sqrt{b d} a b^{2} c^{2} d{\left | b \right |} - 5 \, \sqrt{b d} a^{2} b c d^{2}{\left | b \right |} + \sqrt{b d} a^{3} d^{3}{\left | b \right |}\right )} \log \left ({\left (\sqrt{b d} \sqrt{b x + a} - \sqrt{b^{2} c +{\left (b x + a\right )} b d - a b d}\right )}^{2}\right )}{16 \, b^{4} d} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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